2u+3u^2-8=0

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Solution for 2u+3u^2-8=0 equation: 



2u+3u^2-8=0

a = 3; b = 2; c = -8;
Δ = b2-4ac
Δ = 22-4·3·(-8)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$


$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-10}{2*3}=\frac{-12}{6}
=-2
$


$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+10}{2*3}=\frac{8}{6}
=1+1/3
$

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